Optimal. Leaf size=390 \[ -\frac {3 b c d x^{m+2} \sqrt {c^2 d x^2+d} \, _3F_2\left (1,\frac {m}{2}+1,\frac {m}{2}+1;\frac {m}{2}+\frac {3}{2},\frac {m}{2}+2;-c^2 x^2\right )}{(m+1) (m+2)^2 (m+4) \sqrt {c^2 x^2+1}}+\frac {3 d x^{m+1} \sqrt {c^2 d x^2+d} \, _2F_1\left (\frac {1}{2},\frac {m+1}{2};\frac {m+3}{2};-c^2 x^2\right ) \left (a+b \sinh ^{-1}(c x)\right )}{\left (m^3+7 m^2+14 m+8\right ) \sqrt {c^2 x^2+1}}+\frac {3 d x^{m+1} \sqrt {c^2 d x^2+d} \left (a+b \sinh ^{-1}(c x)\right )}{m^2+6 m+8}+\frac {x^{m+1} \left (c^2 d x^2+d\right )^{3/2} \left (a+b \sinh ^{-1}(c x)\right )}{m+4}-\frac {b c d x^{m+2} \sqrt {c^2 d x^2+d}}{\left (m^2+6 m+8\right ) \sqrt {c^2 x^2+1}}-\frac {3 b c d x^{m+2} \sqrt {c^2 d x^2+d}}{(m+2)^2 (m+4) \sqrt {c^2 x^2+1}}-\frac {b c^3 d x^{m+4} \sqrt {c^2 d x^2+d}}{(m+4)^2 \sqrt {c^2 x^2+1}} \]
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Rubi [A] time = 0.33, antiderivative size = 390, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, integrand size = 26, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.192, Rules used = {5744, 5742, 5762, 30, 14} \[ -\frac {3 b c d x^{m+2} \sqrt {c^2 d x^2+d} \, _3F_2\left (1,\frac {m}{2}+1,\frac {m}{2}+1;\frac {m}{2}+\frac {3}{2},\frac {m}{2}+2;-c^2 x^2\right )}{(m+1) (m+2)^2 (m+4) \sqrt {c^2 x^2+1}}+\frac {3 d x^{m+1} \sqrt {c^2 d x^2+d} \, _2F_1\left (\frac {1}{2},\frac {m+1}{2};\frac {m+3}{2};-c^2 x^2\right ) \left (a+b \sinh ^{-1}(c x)\right )}{\left (m^3+7 m^2+14 m+8\right ) \sqrt {c^2 x^2+1}}+\frac {3 d x^{m+1} \sqrt {c^2 d x^2+d} \left (a+b \sinh ^{-1}(c x)\right )}{m^2+6 m+8}+\frac {x^{m+1} \left (c^2 d x^2+d\right )^{3/2} \left (a+b \sinh ^{-1}(c x)\right )}{m+4}-\frac {b c d x^{m+2} \sqrt {c^2 d x^2+d}}{\left (m^2+6 m+8\right ) \sqrt {c^2 x^2+1}}-\frac {3 b c d x^{m+2} \sqrt {c^2 d x^2+d}}{(m+2)^2 (m+4) \sqrt {c^2 x^2+1}}-\frac {b c^3 d x^{m+4} \sqrt {c^2 d x^2+d}}{(m+4)^2 \sqrt {c^2 x^2+1}} \]
Antiderivative was successfully verified.
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Rule 14
Rule 30
Rule 5742
Rule 5744
Rule 5762
Rubi steps
\begin {align*} \int x^m \left (d+c^2 d x^2\right )^{3/2} \left (a+b \sinh ^{-1}(c x)\right ) \, dx &=\frac {x^{1+m} \left (d+c^2 d x^2\right )^{3/2} \left (a+b \sinh ^{-1}(c x)\right )}{4+m}+\frac {(3 d) \int x^m \sqrt {d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right ) \, dx}{4+m}-\frac {\left (b c d \sqrt {d+c^2 d x^2}\right ) \int x^{1+m} \left (1+c^2 x^2\right ) \, dx}{(4+m) \sqrt {1+c^2 x^2}}\\ &=\frac {3 d x^{1+m} \sqrt {d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )}{8+6 m+m^2}+\frac {x^{1+m} \left (d+c^2 d x^2\right )^{3/2} \left (a+b \sinh ^{-1}(c x)\right )}{4+m}-\frac {\left (b c d \sqrt {d+c^2 d x^2}\right ) \int \left (x^{1+m}+c^2 x^{3+m}\right ) \, dx}{(4+m) \sqrt {1+c^2 x^2}}+\frac {\left (3 d \sqrt {d+c^2 d x^2}\right ) \int \frac {x^m \left (a+b \sinh ^{-1}(c x)\right )}{\sqrt {1+c^2 x^2}} \, dx}{(2+m) (4+m) \sqrt {1+c^2 x^2}}-\frac {\left (3 b c d \sqrt {d+c^2 d x^2}\right ) \int x^{1+m} \, dx}{(2+m) (4+m) \sqrt {1+c^2 x^2}}\\ &=-\frac {3 b c d x^{2+m} \sqrt {d+c^2 d x^2}}{(2+m)^2 (4+m) \sqrt {1+c^2 x^2}}-\frac {b c d x^{2+m} \sqrt {d+c^2 d x^2}}{\left (8+6 m+m^2\right ) \sqrt {1+c^2 x^2}}-\frac {b c^3 d x^{4+m} \sqrt {d+c^2 d x^2}}{(4+m)^2 \sqrt {1+c^2 x^2}}+\frac {3 d x^{1+m} \sqrt {d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )}{8+6 m+m^2}+\frac {x^{1+m} \left (d+c^2 d x^2\right )^{3/2} \left (a+b \sinh ^{-1}(c x)\right )}{4+m}+\frac {3 d x^{1+m} \sqrt {d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right ) \, _2F_1\left (\frac {1}{2},\frac {1+m}{2};\frac {3+m}{2};-c^2 x^2\right )}{\left (8+14 m+7 m^2+m^3\right ) \sqrt {1+c^2 x^2}}-\frac {3 b c d x^{2+m} \sqrt {d+c^2 d x^2} \, _3F_2\left (1,1+\frac {m}{2},1+\frac {m}{2};\frac {3}{2}+\frac {m}{2},2+\frac {m}{2};-c^2 x^2\right )}{(1+m) (2+m)^2 (4+m) \sqrt {1+c^2 x^2}}\\ \end {align*}
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Mathematica [A] time = 0.52, size = 233, normalized size = 0.60 \[ \frac {d x^{m+1} \sqrt {c^2 d x^2+d} \left (-\frac {3 \left (b c x \, _3F_2\left (1,\frac {m}{2}+1,\frac {m}{2}+1;\frac {m}{2}+\frac {3}{2},\frac {m}{2}+2;-c^2 x^2\right )-(m+2) \, _2F_1\left (\frac {1}{2},\frac {m+1}{2};\frac {m+3}{2};-c^2 x^2\right ) \left (a+b \sinh ^{-1}(c x)\right )-(m+1) (m+2) \sqrt {c^2 x^2+1} \left (a+b \sinh ^{-1}(c x)\right )+b c (m+1) x\right )}{(m+1) (m+2)^2 \sqrt {c^2 x^2+1}}+\left (c^2 x^2+1\right ) \left (a+b \sinh ^{-1}(c x)\right )-\frac {b c x \left (c^2 (m+2) x^2+m+4\right )}{(m+2) (m+4) \sqrt {c^2 x^2+1}}\right )}{m+4} \]
Antiderivative was successfully verified.
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fricas [F] time = 0.53, size = 0, normalized size = 0.00 \[ {\rm integral}\left ({\left (a c^{2} d x^{2} + a d + {\left (b c^{2} d x^{2} + b d\right )} \operatorname {arsinh}\left (c x\right )\right )} \sqrt {c^{2} d x^{2} + d} x^{m}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F(-2)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: TypeError} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [F] time = 1.42, size = 0, normalized size = 0.00 \[ \int x^{m} \left (c^{2} d \,x^{2}+d \right )^{\frac {3}{2}} \left (a +b \arcsinh \left (c x \right )\right )\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int {\left (c^{2} d x^{2} + d\right )}^{\frac {3}{2}} {\left (b \operatorname {arsinh}\left (c x\right ) + a\right )} x^{m}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int x^m\,\left (a+b\,\mathrm {asinh}\left (c\,x\right )\right )\,{\left (d\,c^2\,x^2+d\right )}^{3/2} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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